Skip to main content

Courses









Comments

Post a Comment

Popular posts from this blog

( ANSYS APDL THERMAL ) Basic 1D Conduction Example.

Preference > thermal > ok Pre-processor >element type > add/edit/delete > add > solid > quad 4 node 55 > ok > close. Pre - processor > material properties> material models > thermal > conductivity >  isotropic > KXX = 16 > exit. Pre - processor > modelling > create > area > rectangle > by 2 corners ( enter width =1, enter height =1) > ok. Pre - processor > meshing > size control > manual size  > lines > picked lines > (select two lines opposite to each other or parallel to each other) > ok > No of element divisions = 10 > apply > (select remaining two lines of the square which are also parallel to each other) > ok > No of element divisions = 10 > ok. Pre - processor > meshing > mesh > area > free > (select the area) > ok. Pre - processor > loads > analysis type > new analysis > steady state > ok. Pr...
Post a Comment
Read more

(ANSYS APDL THERMAL) Basic Heat Transfer example with heat generation

Preference > thermal > ok Pre-processor >element type > add/edit/delete > add > solid > quad 4 node 55 > ok > close. Pre - processor > material properties> material models > thermal > conductivity >    isotropic > KXX = 100 > exit. Pre - processor > modelling > create > area > rectangle > by 2 corners ( enter width =1, enter height =1) > ok. Pre - processor > meshing > size control > manual size  > lines > picked lines > (select two lines opposite to each other or parallel to each other) > ok > No of element divisions = 10 > apply > (select remaining two lines of the square which are also parallel to each other) > ok > No of element divisions = 10 > ok. Pre - processor > meshing > mesh > area > free > (select the area) > ok. Pre - processor > loads > analysis type > new analysis > steady state ...
Post a Comment
Read more

(ANSYS APDL STRUCTURAL) Modal analysis of a spring-mass system.

Determine the normal and natural frequency of the system below for the values of the masses and the spring stiffness gives. Solution > analysis types mode frequency analysis (ANTYPE = 2) & element type is spring damper element (COMBI 14), Structural mass element (MASS 21). Assumptions: The spring length is arbitrary selected and are used only to define the spring direction, modal analysis is performed using blocked Lanczos Eigensolver. We get f1=2.5814, f2=8.3263, A1/A2=0.9212, A1/A2=-2.1712 (where A1=NODE 2, A2=NODE 3) Pre-processor > element type > add/edit/delete > add > structural mass (mass21) > apply > combination > spring damper 14 > ok. Pre-processor > element type > add/edit/delete> select Mass 21 > options > set (K1 = masses inertias, K2 = parallel to global, K3 = 2-D w/o rot iner) > ok. Pre-processor > element type > add/edit/delete> select Combi 14 > options > set ...
Post a Comment
Read more

For Online Classes

Name

Email *

Message *